Files
sub2api/backend/internal/service/gateway_account_selection_test.go
yangjianbo bb5a5dd65e test: 完善自动化测试体系(7个模块,73个任务)
系统性地修复、补充和强化项目的自动化测试能力:

1. 测试基础设施修复
   - 修复 stubConcurrencyCache 缺失方法和构造函数参数不匹配
   - 创建 testutil 共享包(stubs.go, fixtures.go, httptest.go)
   - 为所有 Stub 添加编译期接口断言

2. 中间件测试补充
   - 新增 JWT 认证中间件测试(有效/过期/篡改/缺失 Token)
   - 补充 rate_limiter 和 recovery 中间件测试场景

3. 网关核心路径测试
   - 新增账户选择、等待队列、流式响应、并发控制、计费、Claude Code 检测测试
   - 覆盖负载均衡、粘性会话、SSE 转发、槽位管理等关键逻辑

4. 前端测试体系(11个新测试文件,163个测试用例)
   - Pinia stores: auth, app, subscriptions
   - API client: 请求拦截器、响应拦截器、401 刷新
   - Router guards: 认证重定向、管理员权限、简易模式限制
   - Composables: useForm, useTableLoader, useClipboard
   - Components: LoginForm, ApiKeyCreate, Dashboard

5. CI/CD 流水线重构
   - 重构 backend-ci.yml 为统一的 ci.yml
   - 前后端 4 个并行 Job + Postgres/Redis services
   - Race 检测、覆盖率收集与门禁、Docker 构建验证

6. E2E 自动化测试
   - e2e-test.sh 自动化脚本(Docker 启动→健康检查→测试→清理)
   - 用户注册→登录→API Key→网关调用完整链路测试
   - Mock 模式和 API Key 脱敏支持

7. 修复预存问题
   - tlsfingerprint dialer_test.go 缺失 build tag 导致集成测试编译冲突

Co-Authored-By: Claude Opus 4.6 <noreply@anthropic.com>
2026-02-08 12:05:39 +08:00

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//go:build unit
package service
import (
"testing"
"time"
"github.com/stretchr/testify/require"
)
// --- helpers ---
func testTimePtr(t time.Time) *time.Time { return &t }
func makeAccWithLoad(id int64, priority int, loadRate int, lastUsed *time.Time, accType string) accountWithLoad {
return accountWithLoad{
account: &Account{
ID: id,
Priority: priority,
LastUsedAt: lastUsed,
Type: accType,
Schedulable: true,
Status: StatusActive,
},
loadInfo: &AccountLoadInfo{
AccountID: id,
CurrentConcurrency: 0,
LoadRate: loadRate,
},
}
}
// --- sortAccountsByPriorityAndLastUsed ---
func TestSortAccountsByPriorityAndLastUsed_ByPriority(t *testing.T) {
now := time.Now()
accounts := []*Account{
{ID: 1, Priority: 5, LastUsedAt: testTimePtr(now)},
{ID: 2, Priority: 1, LastUsedAt: testTimePtr(now)},
{ID: 3, Priority: 3, LastUsedAt: testTimePtr(now)},
}
sortAccountsByPriorityAndLastUsed(accounts, false)
require.Equal(t, int64(2), accounts[0].ID, "优先级最低的排第一")
require.Equal(t, int64(3), accounts[1].ID)
require.Equal(t, int64(1), accounts[2].ID)
}
func TestSortAccountsByPriorityAndLastUsed_SamePriorityByLastUsed(t *testing.T) {
now := time.Now()
accounts := []*Account{
{ID: 1, Priority: 1, LastUsedAt: testTimePtr(now)},
{ID: 2, Priority: 1, LastUsedAt: testTimePtr(now.Add(-1 * time.Hour))},
{ID: 3, Priority: 1, LastUsedAt: nil},
}
sortAccountsByPriorityAndLastUsed(accounts, false)
require.Equal(t, int64(3), accounts[0].ID, "nil LastUsedAt 排最前")
require.Equal(t, int64(2), accounts[1].ID, "更早使用的排前面")
require.Equal(t, int64(1), accounts[2].ID)
}
func TestSortAccountsByPriorityAndLastUsed_PreferOAuth(t *testing.T) {
accounts := []*Account{
{ID: 1, Priority: 1, LastUsedAt: nil, Type: AccountTypeAPIKey},
{ID: 2, Priority: 1, LastUsedAt: nil, Type: AccountTypeOAuth},
}
sortAccountsByPriorityAndLastUsed(accounts, true)
require.Equal(t, int64(2), accounts[0].ID, "preferOAuth 时 OAuth 账号排前面")
}
func TestSortAccountsByPriorityAndLastUsed_StableSort(t *testing.T) {
accounts := []*Account{
{ID: 1, Priority: 1, LastUsedAt: nil, Type: AccountTypeAPIKey},
{ID: 2, Priority: 1, LastUsedAt: nil, Type: AccountTypeAPIKey},
{ID: 3, Priority: 1, LastUsedAt: nil, Type: AccountTypeAPIKey},
}
sortAccountsByPriorityAndLastUsed(accounts, false)
// 稳定排序:相同键值的元素保持原始顺序
require.Equal(t, int64(1), accounts[0].ID)
require.Equal(t, int64(2), accounts[1].ID)
require.Equal(t, int64(3), accounts[2].ID)
}
func TestSortAccountsByPriorityAndLastUsed_MixedPriorityAndTime(t *testing.T) {
now := time.Now()
accounts := []*Account{
{ID: 1, Priority: 2, LastUsedAt: nil},
{ID: 2, Priority: 1, LastUsedAt: testTimePtr(now)},
{ID: 3, Priority: 1, LastUsedAt: testTimePtr(now.Add(-1 * time.Hour))},
{ID: 4, Priority: 2, LastUsedAt: testTimePtr(now.Add(-2 * time.Hour))},
}
sortAccountsByPriorityAndLastUsed(accounts, false)
// 优先级1排前nil < earlier
require.Equal(t, int64(3), accounts[0].ID, "优先级1 + 更早")
require.Equal(t, int64(2), accounts[1].ID, "优先级1 + 现在")
// 优先级2排后nil < time
require.Equal(t, int64(1), accounts[2].ID, "优先级2 + nil")
require.Equal(t, int64(4), accounts[3].ID, "优先级2 + 有时间")
}
// --- selectByCallCount ---
func TestSelectByCallCount_Empty(t *testing.T) {
result := selectByCallCount(nil, nil, false)
require.Nil(t, result)
}
func TestSelectByCallCount_Single(t *testing.T) {
accounts := []accountWithLoad{
makeAccWithLoad(1, 1, 50, nil, AccountTypeAPIKey),
}
result := selectByCallCount(accounts, map[int64]*ModelLoadInfo{1: {CallCount: 10}}, false)
require.NotNil(t, result)
require.Equal(t, int64(1), result.account.ID)
}
func TestSelectByCallCount_NilModelLoadFallsBackToLRU(t *testing.T) {
now := time.Now()
accounts := []accountWithLoad{
makeAccWithLoad(1, 1, 50, testTimePtr(now), AccountTypeAPIKey),
makeAccWithLoad(2, 1, 50, testTimePtr(now.Add(-1*time.Hour)), AccountTypeAPIKey),
}
result := selectByCallCount(accounts, nil, false)
require.NotNil(t, result)
require.Equal(t, int64(2), result.account.ID, "nil modelLoadMap 应回退到 LRU 选择")
}
func TestSelectByCallCount_SelectsMinCallCount(t *testing.T) {
accounts := []accountWithLoad{
makeAccWithLoad(1, 1, 50, nil, AccountTypeAPIKey),
makeAccWithLoad(2, 1, 50, nil, AccountTypeAPIKey),
makeAccWithLoad(3, 1, 50, nil, AccountTypeAPIKey),
}
modelLoad := map[int64]*ModelLoadInfo{
1: {CallCount: 100},
2: {CallCount: 5},
3: {CallCount: 50},
}
// 运行多次确认总是选调用次数最少的
for i := 0; i < 10; i++ {
result := selectByCallCount(accounts, modelLoad, false)
require.NotNil(t, result)
require.Equal(t, int64(2), result.account.ID, "应选择调用次数最少的账号")
}
}
func TestSelectByCallCount_NewAccountUsesAverage(t *testing.T) {
accounts := []accountWithLoad{
makeAccWithLoad(1, 1, 50, nil, AccountTypeAPIKey),
makeAccWithLoad(2, 1, 50, nil, AccountTypeAPIKey),
makeAccWithLoad(3, 1, 50, nil, AccountTypeAPIKey),
}
// 账号1和2有调用记录账号3是新账号CallCount=0
// 平均调用次数 = (100 + 200) / 2 = 150
// 新账号用平均值 150比账号1(100)多所以应选账号1
modelLoad := map[int64]*ModelLoadInfo{
1: {CallCount: 100},
2: {CallCount: 200},
// 3 没有记录
}
for i := 0; i < 10; i++ {
result := selectByCallCount(accounts, modelLoad, false)
require.NotNil(t, result)
require.Equal(t, int64(1), result.account.ID, "新账号虚拟调用次数(150)高于账号1(100)应选账号1")
}
}
func TestSelectByCallCount_AllNewAccountsFallToAvgZero(t *testing.T) {
accounts := []accountWithLoad{
makeAccWithLoad(1, 1, 50, nil, AccountTypeAPIKey),
makeAccWithLoad(2, 1, 50, nil, AccountTypeAPIKey),
}
// 所有账号都是新的avgCallCount = 0所有人 effectiveCallCount 都是 0
modelLoad := map[int64]*ModelLoadInfo{}
validIDs := map[int64]bool{1: true, 2: true}
for i := 0; i < 10; i++ {
result := selectByCallCount(accounts, modelLoad, false)
require.NotNil(t, result)
require.True(t, validIDs[result.account.ID], "所有新账号应随机选择")
}
}
func TestSelectByCallCount_PreferOAuth(t *testing.T) {
accounts := []accountWithLoad{
makeAccWithLoad(1, 1, 50, nil, AccountTypeAPIKey),
makeAccWithLoad(2, 1, 50, nil, AccountTypeOAuth),
}
// 两个账号调用次数相同
modelLoad := map[int64]*ModelLoadInfo{
1: {CallCount: 10},
2: {CallCount: 10},
}
for i := 0; i < 10; i++ {
result := selectByCallCount(accounts, modelLoad, true)
require.NotNil(t, result)
require.Equal(t, int64(2), result.account.ID, "调用次数相同时应优先选择 OAuth 账号")
}
}