test: 完善自动化测试体系（7个模块，73个任务）
系统性地修复、补充和强化项目的自动化测试能力： 1. 测试基础设施修复 - 修复 stubConcurrencyCache 缺失方法和构造函数参数不匹配 - 创建 testutil 共享包（stubs.go, fixtures.go, httptest.go） - 为所有 Stub 添加编译期接口断言 2. 中间件测试补充 - 新增 JWT 认证中间件测试（有效/过期/篡改/缺失 Token） - 补充 rate_limiter 和 recovery 中间件测试场景 3. 网关核心路径测试 - 新增账户选择、等待队列、流式响应、并发控制、计费、Claude Code 检测测试 - 覆盖负载均衡、粘性会话、SSE 转发、槽位管理等关键逻辑 4. 前端测试体系（11个新测试文件，163个测试用例） - Pinia stores: auth, app, subscriptions - API client: 请求拦截器、响应拦截器、401 刷新 - Router guards: 认证重定向、管理员权限、简易模式限制 - Composables: useForm, useTableLoader, useClipboard - Components: LoginForm, ApiKeyCreate, Dashboard 5. CI/CD 流水线重构 - 重构 backend-ci.yml 为统一的 ci.yml - 前后端 4 个并行 Job + Postgres/Redis services - Race 检测、覆盖率收集与门禁、Docker 构建验证 6. E2E 自动化测试 - e2e-test.sh 自动化脚本（Docker 启动→健康检查→测试→清理） - 用户注册→登录→API Key→网关调用完整链路测试 - Mock 模式和 API Key 脱敏支持 7. 修复预存问题 - tlsfingerprint dialer_test.go 缺失 build tag 导致集成测试编译冲突 Co-Authored-By: Claude Opus 4.6 <noreply@anthropic.com>
This commit is contained in:
yangjianbo
198
backend/internal/service/gateway_account_selection_test.go
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198
backend/internal/service/gateway_account_selection_test.go
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//go:build unit
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package service
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import (
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"testing"
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"time"
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"github.com/stretchr/testify/require"
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)
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// --- helpers ---
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func testTimePtr(t time.Time) *time.Time { return &t }
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func makeAccWithLoad(id int64, priority int, loadRate int, lastUsed *time.Time, accType string) accountWithLoad {
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return accountWithLoad{
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account: &Account{
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ID: id,
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Priority: priority,
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LastUsedAt: lastUsed,
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Type: accType,
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Schedulable: true,
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Status: StatusActive,
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},
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loadInfo: &AccountLoadInfo{
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AccountID: id,
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CurrentConcurrency: 0,
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LoadRate: loadRate,
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},
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}
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}
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// --- sortAccountsByPriorityAndLastUsed ---
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func TestSortAccountsByPriorityAndLastUsed_ByPriority(t *testing.T) {
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now := time.Now()
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accounts := []*Account{
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{ID: 1, Priority: 5, LastUsedAt: testTimePtr(now)},
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{ID: 2, Priority: 1, LastUsedAt: testTimePtr(now)},
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{ID: 3, Priority: 3, LastUsedAt: testTimePtr(now)},
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}
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sortAccountsByPriorityAndLastUsed(accounts, false)
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require.Equal(t, int64(2), accounts[0].ID, "优先级最低的排第一")
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require.Equal(t, int64(3), accounts[1].ID)
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require.Equal(t, int64(1), accounts[2].ID)
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}
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func TestSortAccountsByPriorityAndLastUsed_SamePriorityByLastUsed(t *testing.T) {
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now := time.Now()
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accounts := []*Account{
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{ID: 1, Priority: 1, LastUsedAt: testTimePtr(now)},
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{ID: 2, Priority: 1, LastUsedAt: testTimePtr(now.Add(-1 * time.Hour))},
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{ID: 3, Priority: 1, LastUsedAt: nil},
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}
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sortAccountsByPriorityAndLastUsed(accounts, false)
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require.Equal(t, int64(3), accounts[0].ID, "nil LastUsedAt 排最前")
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require.Equal(t, int64(2), accounts[1].ID, "更早使用的排前面")
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require.Equal(t, int64(1), accounts[2].ID)
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}
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func TestSortAccountsByPriorityAndLastUsed_PreferOAuth(t *testing.T) {
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accounts := []*Account{
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{ID: 1, Priority: 1, LastUsedAt: nil, Type: AccountTypeAPIKey},
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{ID: 2, Priority: 1, LastUsedAt: nil, Type: AccountTypeOAuth},
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}
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sortAccountsByPriorityAndLastUsed(accounts, true)
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require.Equal(t, int64(2), accounts[0].ID, "preferOAuth 时 OAuth 账号排前面")
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}
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func TestSortAccountsByPriorityAndLastUsed_StableSort(t *testing.T) {
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accounts := []*Account{
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{ID: 1, Priority: 1, LastUsedAt: nil, Type: AccountTypeAPIKey},
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{ID: 2, Priority: 1, LastUsedAt: nil, Type: AccountTypeAPIKey},
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{ID: 3, Priority: 1, LastUsedAt: nil, Type: AccountTypeAPIKey},
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}
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sortAccountsByPriorityAndLastUsed(accounts, false)
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// 稳定排序：相同键值的元素保持原始顺序
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require.Equal(t, int64(1), accounts[0].ID)
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require.Equal(t, int64(2), accounts[1].ID)
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require.Equal(t, int64(3), accounts[2].ID)
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}
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func TestSortAccountsByPriorityAndLastUsed_MixedPriorityAndTime(t *testing.T) {
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now := time.Now()
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accounts := []*Account{
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{ID: 1, Priority: 2, LastUsedAt: nil},
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{ID: 2, Priority: 1, LastUsedAt: testTimePtr(now)},
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{ID: 3, Priority: 1, LastUsedAt: testTimePtr(now.Add(-1 * time.Hour))},
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{ID: 4, Priority: 2, LastUsedAt: testTimePtr(now.Add(-2 * time.Hour))},
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}
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sortAccountsByPriorityAndLastUsed(accounts, false)
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// 优先级1排前：nil < earlier
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require.Equal(t, int64(3), accounts[0].ID, "优先级1 + 更早")
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require.Equal(t, int64(2), accounts[1].ID, "优先级1 + 现在")
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// 优先级2排后：nil < time
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require.Equal(t, int64(1), accounts[2].ID, "优先级2 + nil")
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require.Equal(t, int64(4), accounts[3].ID, "优先级2 + 有时间")
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}
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// --- selectByCallCount ---
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func TestSelectByCallCount_Empty(t *testing.T) {
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result := selectByCallCount(nil, nil, false)
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require.Nil(t, result)
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}
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func TestSelectByCallCount_Single(t *testing.T) {
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accounts := []accountWithLoad{
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makeAccWithLoad(1, 1, 50, nil, AccountTypeAPIKey),
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}
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result := selectByCallCount(accounts, map[int64]*ModelLoadInfo{1: {CallCount: 10}}, false)
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require.NotNil(t, result)
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require.Equal(t, int64(1), result.account.ID)
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}
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func TestSelectByCallCount_NilModelLoadFallsBackToLRU(t *testing.T) {
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now := time.Now()
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accounts := []accountWithLoad{
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makeAccWithLoad(1, 1, 50, testTimePtr(now), AccountTypeAPIKey),
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makeAccWithLoad(2, 1, 50, testTimePtr(now.Add(-1*time.Hour)), AccountTypeAPIKey),
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}
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result := selectByCallCount(accounts, nil, false)
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require.NotNil(t, result)
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require.Equal(t, int64(2), result.account.ID, "nil modelLoadMap 应回退到 LRU 选择")
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}
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func TestSelectByCallCount_SelectsMinCallCount(t *testing.T) {
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accounts := []accountWithLoad{
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makeAccWithLoad(1, 1, 50, nil, AccountTypeAPIKey),
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makeAccWithLoad(2, 1, 50, nil, AccountTypeAPIKey),
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makeAccWithLoad(3, 1, 50, nil, AccountTypeAPIKey),
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}
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modelLoad := map[int64]*ModelLoadInfo{
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1: {CallCount: 100},
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2: {CallCount: 5},
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3: {CallCount: 50},
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}
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// 运行多次确认总是选调用次数最少的
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for i := 0; i < 10; i++ {
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result := selectByCallCount(accounts, modelLoad, false)
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require.NotNil(t, result)
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require.Equal(t, int64(2), result.account.ID, "应选择调用次数最少的账号")
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}
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}
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func TestSelectByCallCount_NewAccountUsesAverage(t *testing.T) {
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accounts := []accountWithLoad{
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makeAccWithLoad(1, 1, 50, nil, AccountTypeAPIKey),
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makeAccWithLoad(2, 1, 50, nil, AccountTypeAPIKey),
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makeAccWithLoad(3, 1, 50, nil, AccountTypeAPIKey),
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}
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// 账号1和2有调用记录，账号3是新账号（CallCount=0）
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// 平均调用次数 = (100 + 200) / 2 = 150
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// 新账号用平均值 150，比账号1(100)多，所以应选账号1
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modelLoad := map[int64]*ModelLoadInfo{
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1: {CallCount: 100},
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2: {CallCount: 200},
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// 3 没有记录
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}
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for i := 0; i < 10; i++ {
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result := selectByCallCount(accounts, modelLoad, false)
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require.NotNil(t, result)
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require.Equal(t, int64(1), result.account.ID, "新账号虚拟调用次数(150)高于账号1(100)，应选账号1")
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}
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}
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func TestSelectByCallCount_AllNewAccountsFallToAvgZero(t *testing.T) {
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accounts := []accountWithLoad{
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makeAccWithLoad(1, 1, 50, nil, AccountTypeAPIKey),
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makeAccWithLoad(2, 1, 50, nil, AccountTypeAPIKey),
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}
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// 所有账号都是新的，avgCallCount = 0，所有人 effectiveCallCount 都是 0
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modelLoad := map[int64]*ModelLoadInfo{}
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validIDs := map[int64]bool{1: true, 2: true}
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for i := 0; i < 10; i++ {
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result := selectByCallCount(accounts, modelLoad, false)
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require.NotNil(t, result)
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require.True(t, validIDs[result.account.ID], "所有新账号应随机选择")
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}
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}
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func TestSelectByCallCount_PreferOAuth(t *testing.T) {
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accounts := []accountWithLoad{
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makeAccWithLoad(1, 1, 50, nil, AccountTypeAPIKey),
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makeAccWithLoad(2, 1, 50, nil, AccountTypeOAuth),
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}
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// 两个账号调用次数相同
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modelLoad := map[int64]*ModelLoadInfo{
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1: {CallCount: 10},
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2: {CallCount: 10},
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}
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for i := 0; i < 10; i++ {
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result := selectByCallCount(accounts, modelLoad, true)
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require.NotNil(t, result)
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require.Equal(t, int64(2), result.account.ID, "调用次数相同时应优先选择 OAuth 账号")
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}
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}
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