修改403逻辑: 先临时冷却,再根据连续次数决定是否判坏号

This commit is contained in:
wx-11
2026-04-23 12:58:13 +08:00
parent eea6f38881
commit 11cf23da7d
11 changed files with 370 additions and 17 deletions

View File

@@ -0,0 +1,51 @@
package repository
import (
"context"
"fmt"
"github.com/Wei-Shaw/sub2api/internal/service"
"github.com/redis/go-redis/v9"
)
const openAI403CounterPrefix = "openai_403_count:account:"
var openAI403CounterIncrScript = redis.NewScript(`
local key = KEYS[1]
local ttl = tonumber(ARGV[1])
local count = redis.call('INCR', key)
if count == 1 then
redis.call('EXPIRE', key, ttl)
end
return count
`)
type openAI403CounterCache struct {
rdb *redis.Client
}
func NewOpenAI403CounterCache(rdb *redis.Client) service.OpenAI403CounterCache {
return &openAI403CounterCache{rdb: rdb}
}
func (c *openAI403CounterCache) IncrementOpenAI403Count(ctx context.Context, accountID int64, windowMinutes int) (int64, error) {
key := fmt.Sprintf("%s%d", openAI403CounterPrefix, accountID)
ttlSeconds := windowMinutes * 60
if ttlSeconds < 60 {
ttlSeconds = 60
}
result, err := openAI403CounterIncrScript.Run(ctx, c.rdb, []string{key}, ttlSeconds).Int64()
if err != nil {
return 0, fmt.Errorf("increment openai 403 count: %w", err)
}
return result, nil
}
func (c *openAI403CounterCache) ResetOpenAI403Count(ctx context.Context, accountID int64) error {
key := fmt.Sprintf("%s%d", openAI403CounterPrefix, accountID)
return c.rdb.Del(ctx, key).Err()
}